Optimal. Leaf size=203 \[ \frac {a^2 d^2 \cot (e+f x) (d \csc (e+f x))^{-2+n}}{f (1-n)}+\frac {2 a^2 d^2 \cos (e+f x) (d \csc (e+f x))^{-2+n} \, _2F_1\left (\frac {1}{2},\frac {2-n}{2};\frac {4-n}{2};\sin ^2(e+f x)\right )}{f (2-n) \sqrt {\cos ^2(e+f x)}}+\frac {a^2 d^3 (3-2 n) \cos (e+f x) (d \csc (e+f x))^{-3+n} \, _2F_1\left (\frac {1}{2},\frac {3-n}{2};\frac {5-n}{2};\sin ^2(e+f x)\right )}{f (1-n) (3-n) \sqrt {\cos ^2(e+f x)}} \]
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Rubi [A]
time = 0.17, antiderivative size = 203, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 5, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {3317, 3873,
3857, 2722, 4131} \begin {gather*} \frac {a^2 d^3 (3-2 n) \cos (e+f x) (d \csc (e+f x))^{n-3} \, _2F_1\left (\frac {1}{2},\frac {3-n}{2};\frac {5-n}{2};\sin ^2(e+f x)\right )}{f (1-n) (3-n) \sqrt {\cos ^2(e+f x)}}+\frac {2 a^2 d^2 \cos (e+f x) (d \csc (e+f x))^{n-2} \, _2F_1\left (\frac {1}{2},\frac {2-n}{2};\frac {4-n}{2};\sin ^2(e+f x)\right )}{f (2-n) \sqrt {\cos ^2(e+f x)}}+\frac {a^2 d^2 \cot (e+f x) (d \csc (e+f x))^{n-2}}{f (1-n)} \end {gather*}
Antiderivative was successfully verified.
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Rule 2722
Rule 3317
Rule 3857
Rule 3873
Rule 4131
Rubi steps
\begin {align*} \int (d \csc (e+f x))^n (a+a \sin (e+f x))^2 \, dx &=d^2 \int (d \csc (e+f x))^{-2+n} (a+a \csc (e+f x))^2 \, dx\\ &=\left (2 a^2 d\right ) \int (d \csc (e+f x))^{-1+n} \, dx+d^2 \int (d \csc (e+f x))^{-2+n} \left (a^2+a^2 \csc ^2(e+f x)\right ) \, dx\\ &=\frac {a^2 d^2 \cot (e+f x) (d \csc (e+f x))^{-2+n}}{f (1-n)}+\frac {\left (a^2 d^2 (3-2 n)\right ) \int (d \csc (e+f x))^{-2+n} \, dx}{1-n}+\left (2 a^2 d (d \csc (e+f x))^n \left (\frac {\sin (e+f x)}{d}\right )^n\right ) \int \left (\frac {\sin (e+f x)}{d}\right )^{1-n} \, dx\\ &=\frac {a^2 d^2 \cot (e+f x) (d \csc (e+f x))^{-2+n}}{f (1-n)}+\frac {2 a^2 \cos (e+f x) (d \csc (e+f x))^n \, _2F_1\left (\frac {1}{2},\frac {2-n}{2};\frac {4-n}{2};\sin ^2(e+f x)\right ) \sin ^2(e+f x)}{f (2-n) \sqrt {\cos ^2(e+f x)}}+\frac {\left (a^2 d^2 (3-2 n) (d \csc (e+f x))^n \left (\frac {\sin (e+f x)}{d}\right )^n\right ) \int \left (\frac {\sin (e+f x)}{d}\right )^{2-n} \, dx}{1-n}\\ &=\frac {a^2 d^2 \cot (e+f x) (d \csc (e+f x))^{-2+n}}{f (1-n)}+\frac {2 a^2 \cos (e+f x) (d \csc (e+f x))^n \, _2F_1\left (\frac {1}{2},\frac {2-n}{2};\frac {4-n}{2};\sin ^2(e+f x)\right ) \sin ^2(e+f x)}{f (2-n) \sqrt {\cos ^2(e+f x)}}+\frac {a^2 (3-2 n) \cos (e+f x) (d \csc (e+f x))^n \, _2F_1\left (\frac {1}{2},\frac {3-n}{2};\frac {5-n}{2};\sin ^2(e+f x)\right ) \sin ^3(e+f x)}{f (1-n) (3-n) \sqrt {\cos ^2(e+f x)}}\\ \end {align*}
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Mathematica [A]
time = 1.29, size = 346, normalized size = 1.70 \begin {gather*} -\frac {2 (d \csc (e+f x))^n \sec ^2\left (\frac {1}{2} (e+f x)\right )^{-n} (a+a \sin (e+f x))^2 \tan \left (\frac {1}{2} (e+f x)\right ) \left ((-2+n) \, _2F_1\left (1-n,\frac {1}{2}-\frac {n}{2};\frac {3}{2}-\frac {n}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )+4 (-2+n) \, _2F_1\left (2-n,\frac {1}{2}-\frac {n}{2};\frac {3}{2}-\frac {n}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )+8 \, _2F_1\left (3-n,\frac {1}{2}-\frac {n}{2};\frac {3}{2}-\frac {n}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )-4 n \, _2F_1\left (3-n,\frac {1}{2}-\frac {n}{2};\frac {3}{2}-\frac {n}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )-4 \, _2F_1\left (2-n,1-\frac {n}{2};2-\frac {n}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right ) \tan \left (\frac {1}{2} (e+f x)\right )+4 n \, _2F_1\left (2-n,1-\frac {n}{2};2-\frac {n}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right ) \tan \left (\frac {1}{2} (e+f x)\right )\right )}{f (-2+n) (-1+n) \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.40, size = 0, normalized size = 0.00 \[\int \left (d \csc \left (f x +e \right )\right )^{n} \left (a +a \sin \left (f x +e \right )\right )^{2}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} a^{2} \left (\int \left (d \csc {\left (e + f x \right )}\right )^{n}\, dx + \int 2 \left (d \csc {\left (e + f x \right )}\right )^{n} \sin {\left (e + f x \right )}\, dx + \int \left (d \csc {\left (e + f x \right )}\right )^{n} \sin ^{2}{\left (e + f x \right )}\, dx\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (\frac {d}{\sin \left (e+f\,x\right )}\right )}^n\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^2 \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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